-5v^2-24v+36=0

Solution for -5v^2-24v+36=0 equation:

-5v^2-24v+36=0

a = -5; b = -24; c = +36;
Δ = b2-4ac
Δ = -242-4·(-5)·36
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*-5}=\frac{-12}{-10}
=1+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*-5}=\frac{60}{-10}
=-6
$